To ask for help with this Maths question

[annie987]

We keep getting 12 but it’s not right. Very frustrated as I’m usually quite good at maths!

13?

It’s 13

A=13

If a was 12 then a squared minus c squared would be zero
a squared = bsquared + c squared
a = square root of the sum of b squared and c squared.

13?

Thank you. Don’t this the 3 glasses of rose have helped matters!!

12 ^2 is 144
You know the answer needs to be 25 as square root of 25 is 5 (b)
So 144 + 25 =169
That is 13 ^2

so to get to 13, you square both sides, giving:
b2 = a2-c^2
so a2=b2+c^2=25+144=169
therefore b=13

13

B=5 & square root of 25 =5 therefore a2-144 = 25
144+25=169
Square root of 169 = 13

Here you go.

If b=5, then the difference between a2 and c2 must be 25 (5=square root of 25). c2 (12*12) = 144. 144+25=169. Square root of 169=13.

Thus a=13

And to check:
1313=169
1212=144
169-144=25
square root of 25=5, which we already know is the value of b.

method -

1. suare both sides gives b squared = a squared - c squared
2. add c squared to both sides gives b squared + c squared = a squared
3. square root both sides gives square root of the sum of b squared and c squared = a

It's 13
If b is 5, then it's the square root of 25
So a squared less c squared = 25
c is 12, so c squared is 144
So a squared must be 144+25=169
making c=13

Yes, I get 13 too.

The square root of 169.

So obvious now! Thanks

I get 13 too.
Square both sides so b2 = a2- c2
a2= b2 + c2
a2 = 25 + 144
a2 = 169
a = 13

(Sorry could do small 2s)

It’s 13.

I got 13 as well.
I still have it!

You all missed one: you could also have a = -13.

Yep. 13.
It's a pythagorean triple. 5,12 and 13.