40+40x0+1 ?

[minimuffy]

40 + 40 x 0 + 1 =

A- 1
B- 41
c- 0

I say its B-41 as you need to multiply then add. (from what i remember of standard grade maths the acroymym BOMDAS- brackets off, multiply, divide, add, subtract)

DH says its 1.

please tell he's wrong!

It's 0, because anything x zero is 0.

And is it handwritten?

Or a text book?

tiger in maths you always do multiply/divide before add/subtract.

so 40 + 40x0 + 1 = 40 + 0 + 1 = 41

can someone tell me what the O in BODMAS is for?

It is 41
40 + 0 + 1 = 41

To be 1 you would need brackets:
( 40 + 40 ) x 0 + 1 = 1

Or a print out?

Oops, didn't read question properly - it's 1.

It is for a child isn't it?

From a school?

Or do you and DH dabble in this sort of thing for fun?

DD1 thinks 41.

No brackets
No exponents
No indices
No divide
Multiply first - 40*0 = 0
Then add = 40+0+1 = 41

but why do you assume the brackets would be around the (40x0)? and not (40+40)

41

Ds yr11 topset says 41 using Bodmas

40 + (40x0) + 1 =
40 + 0 + 1 =
41

As the second 40 needs to be multiplied by 0 first (taking precedence over the addition), I can't see how it can be anything other than 41.

41

not to be a twat or anything but yes, it's 41. Definitely. The level of oaths knowledge is pretty poor on this thread i believe. Multiplication is done first. It could only be 1 if 40+40 was in brackets.

but why do you assume the brackets would be around the (40x0)? and not (40+40)

Because you multiply before you add.

1 is the answer. Isn't it?!

no textbook, its a daft facebook question.....

Atyourcervix: because that's the rule. The "M" in BODMAS tells you the order in which you do things. You don't just read left to right.

Generally, don't the brackets go around multiplication parts of a sequence?