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AIBU?

Share your dilemmas and get honest opinions from other Mumsnetters.

AIBU to ask if anyone can solve this Maths question?

117 replies

Hydrangea444 · 21/05/2022 21:08

DD is doing Further Maths A-Level and is stuck on this question.

AIBU to ask if anyone can solve this Maths question?
OP posts:
Thread gallery
11
Hydrangea444 · 21/05/2022 21:43

eastegg · 21/05/2022 21:34

What has she done before when she hasn’t understood something or has needed help? Surely she doesn’t ask her mum to ask mumsnet?

I don’t know much about maths, but I imagine it’s not going to help her to simply know the answer. She needs guidance on whatever about it she is finding difficult. From maybe er I dunno, a teacher?

Oh why didn't I think of that! Oh hang on, it's Saturday night! I imagine her Maths teacher is enjoying his weekend.
Actually, Mumsnet has provided help with a fair few Maths questions she was stuck on in the past. Never underestimate the power of Mumsnet!

OP posts:
ScootsMcHoy · 21/05/2022 21:45

I don’t know much about maths, but I imagine it’s not going to help her to simply know the answer. She needs guidance on whatever about it she is finding difficult. From maybe er I dunno, a teacher?
That's literally what she's doing though. Nobody is just going to say '17' and then say nothing else. Confused

The A levels start next week.

Seems to me it's not just Maths you don't know much about.

fighoney · 21/05/2022 21:45

Which it is she struggling with? She needs to differentiate the first equation. If she's struggling with the arcsin bit she can Google the rules for differentiating arcsin.
She then needs to simplify the equation until it resembles a number multiplied by the stuff in brackets. (That number is the constant k)

orwellwasright · 21/05/2022 21:45

17

ScootsMcHoy · 21/05/2022 21:47

orwellwasright · 21/05/2022 21:45

17

😂

I hope it is now. You would be a genius, unappreciated in your own lifetime.

Hydrangea444 · 21/05/2022 21:48

Lilimoon · 21/05/2022 21:42

My Yr 10 says there are 2 really helpful vids:

Than you so much!

OP posts:
TheCanyon · 21/05/2022 21:50

Ooh I love maths, I'm away to get a pen and paper. Except when it's my own dd she's a dick that doesn't listen.

RoseDog · 21/05/2022 21:50

My Ds 17 is giving it a go, he's just done his higher maths exam and is hoping to do advanced higher in S6...me and DD 19 don't have a clue!

110APiccadilly · 21/05/2022 21:52

She needs to look up the differential of arcsin - it's a standard one - and if she has a formula sheet for the exam it might be in there - otherwise she should Google it (and make herself a list of differentials to remember as part of her revision!). Then she needs to use chain and product rules to differentiate that first part.

She should then have something which she can manipulate algebraically until she gets the required result.

Familyfallout · 21/05/2022 21:53

My DD had a go but has come back saying this is very complicated and she can't do it... she is sitting her A levels starting next week so either she has a problem or it is just a very hard question!! I am thinking the second option. Sorry not to be more helpful

Bovrilly · 21/05/2022 21:53

Ugh too hard for me and DS is out. With respect to the PP with the Y10, it is way, way, way beyond those introduction to calculus videos. Very tricky.

Mumoftwoinprimary · 21/05/2022 21:55

It has been a very long time since I did A level further maths but I think she needs to use the product rule and the chain rule.

Hydrangea444 · 21/05/2022 21:57

Familyfallout · 21/05/2022 21:53

My DD had a go but has come back saying this is very complicated and she can't do it... she is sitting her A levels starting next week so either she has a problem or it is just a very hard question!! I am thinking the second option. Sorry not to be more helpful

Thanks so much to your DD for having a look at it though 😀

OP posts:
Hydrangea444 · 21/05/2022 22:00

110APiccadilly · 21/05/2022 21:52

She needs to look up the differential of arcsin - it's a standard one - and if she has a formula sheet for the exam it might be in there - otherwise she should Google it (and make herself a list of differentials to remember as part of her revision!). Then she needs to use chain and product rules to differentiate that first part.

She should then have something which she can manipulate algebraically until she gets the required result.

Thank you. DD seems to think she is doing all the required steps but isn't getting to what is the right answer.

OP posts:
LovelyJubbly1234 · 21/05/2022 22:00

a)
y=(4x-3)sqrt(-8(2x^2-3x+1)) + arcsin(4x-3)
y=(4x-3)sqrt(-(16x^2-24x+8)) + arcsin(4x-3)
y=(4x-3)sqrt(-[(4x-3)^2-1]) + arcsin(4x-3)
y=(4x-3)sqrt(1-(4x-3)^2) + arcsin(4x-3)

let u=4x-3
y=u.sqrt(1-u^2) + arcsin(u)
dy/du=(1-u2)(1/2) + u(1/2)(1-u2)(-1/2).(-2u)+(1-u2)-(1/2)
dy/du=2(1-u2)(1/2)

dy/dx=dy/du . du/dx = 2(1-(4x-3)2)(1/2) . 4 = 16sqrt(2).sqrt(-2x^2 + 3x - 1))
k=16sqrt(2)

b)
I = y/k evaluated between 1,1/2
=arcsin(1) - arcsin(-1)
=0

Thanks. One bottle of Chateau Latour under. So apologies for any errors.

lemmein · 21/05/2022 22:03

LovelyJubbly1234 · 21/05/2022 22:00

a)
y=(4x-3)sqrt(-8(2x^2-3x+1)) + arcsin(4x-3)
y=(4x-3)sqrt(-(16x^2-24x+8)) + arcsin(4x-3)
y=(4x-3)sqrt(-[(4x-3)^2-1]) + arcsin(4x-3)
y=(4x-3)sqrt(1-(4x-3)^2) + arcsin(4x-3)

let u=4x-3
y=u.sqrt(1-u^2) + arcsin(u)
dy/du=(1-u2)(1/2) + u(1/2)(1-u2)(-1/2).(-2u)+(1-u2)-(1/2)
dy/du=2(1-u2)(1/2)

dy/dx=dy/du . du/dx = 2(1-(4x-3)2)(1/2) . 4 = 16sqrt(2).sqrt(-2x^2 + 3x - 1))
k=16sqrt(2)

b)
I = y/k evaluated between 1,1/2
=arcsin(1) - arcsin(-1)
=0

Thanks. One bottle of Chateau Latour under. So apologies for any errors.

That's what I was gonna say 🤓

JenniferBarkley · 21/05/2022 22:04

Have to confess I'm a lecturer in a mathematical subject with numerous maths degrees and professional qualifications and I don't fancy that Grin

Tell her to use the product rule and chain rule to differentiate the first part of the expression and look up the derivative of arcsin (not a clue, frankly).

There's two reasons that the answer is included in part a: to give them something to aim for, and so they can do part b even if part a eludes them.

I have no idea about the further maths syllabus but if that's a past paper question I can't imagine it was fully answered by many! So the stronger students will have scored well by eking out as many attempt marks as possible, and by not skipping part b.

Or maybe it's super easy and I'm on a stupid Saturday night!

MissyB1 · 21/05/2022 22:04

Fernsinthegarden · 21/05/2022 21:39

@iex @MrsMorton yep I did exactly the same thing! For some reason was expecting to see ‘if Jan has 5 apples and Ken has 20 apples, how many oranges do they have?’ Or something similar 😂

Even then I would struggle 🤣

JenniferBarkley · 21/05/2022 22:05

@LovelyJubbly1234 feeling much more energetic than me tonight Grin

RubaiyatOfAnyone · 21/05/2022 22:06

Find out how to differentiate arcsins.

use that to do the two parts of the top sum separately, because differentials add. You will probably find that once you’ve differentiated the arcsin it will give you that square-root bit. That will give you K.

for the second bit, it’s asking you to integrate what you’ve just discovered dy over dx was. There’s a factor of k you’ll need to substitute out.

(c) not me, someone who likes maths.

Rattles1 · 21/05/2022 22:06

My husband says he will do it and explain tomorrow. He’s an aerospace engineer ! I’ll revert back if no answer by then and he takes a look

orwellwasright · 21/05/2022 22:07

LovelyJubbly1234 · 21/05/2022 22:00

a)
y=(4x-3)sqrt(-8(2x^2-3x+1)) + arcsin(4x-3)
y=(4x-3)sqrt(-(16x^2-24x+8)) + arcsin(4x-3)
y=(4x-3)sqrt(-[(4x-3)^2-1]) + arcsin(4x-3)
y=(4x-3)sqrt(1-(4x-3)^2) + arcsin(4x-3)

let u=4x-3
y=u.sqrt(1-u^2) + arcsin(u)
dy/du=(1-u2)(1/2) + u(1/2)(1-u2)(-1/2).(-2u)+(1-u2)-(1/2)
dy/du=2(1-u2)(1/2)

dy/dx=dy/du . du/dx = 2(1-(4x-3)2)(1/2) . 4 = 16sqrt(2).sqrt(-2x^2 + 3x - 1))
k=16sqrt(2)

b)
I = y/k evaluated between 1,1/2
=arcsin(1) - arcsin(-1)
=0

Thanks. One bottle of Chateau Latour under. So apologies for any errors.

Niche

Hydrangea444 · 21/05/2022 22:10

LovelyJubbly1234 · 21/05/2022 22:00

a)
y=(4x-3)sqrt(-8(2x^2-3x+1)) + arcsin(4x-3)
y=(4x-3)sqrt(-(16x^2-24x+8)) + arcsin(4x-3)
y=(4x-3)sqrt(-[(4x-3)^2-1]) + arcsin(4x-3)
y=(4x-3)sqrt(1-(4x-3)^2) + arcsin(4x-3)

let u=4x-3
y=u.sqrt(1-u^2) + arcsin(u)
dy/du=(1-u2)(1/2) + u(1/2)(1-u2)(-1/2).(-2u)+(1-u2)-(1/2)
dy/du=2(1-u2)(1/2)

dy/dx=dy/du . du/dx = 2(1-(4x-3)2)(1/2) . 4 = 16sqrt(2).sqrt(-2x^2 + 3x - 1))
k=16sqrt(2)

b)
I = y/k evaluated between 1,1/2
=arcsin(1) - arcsin(-1)
=0

Thanks. One bottle of Chateau Latour under. So apologies for any errors.

Thank you so much! DD said that you have solved it uding a completely different method to the one she had used. That's fantastic!

OP posts:
MotherOfCrocodiles · 21/05/2022 22:18

U = 4x - 3

Chain rule for differentiation

Undertheoldlindentree · 21/05/2022 22:19

I suppose BODMAS doesn't cut it anymore? 😊

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