This quiz is driving me nuts- apparently it's possible?

[Bellyflab]

Can any of you work it out?

Haven't quite got there yet, but:
Q1 doesn't need to be zero as long as the other numerical values sum to zero.
So q10= -(q2+q4+q6+q8) since 2,4,6,8 all have positive answers.
So q5 is F
Q4 must be 2 or more (most likely 2...)
I think you need to choose q1 so as to give 2 as the answer to q6, so that 2 is also the answer to q4...
Not quite there yet, but it's something along these lines

@nillygin

I’ve got the answer if anyone is interested 😁

yes please- may as well post it!

It helps to notice that the answer to question 1 must be a squared number (from question 8). I’ll come back later and explain further if required. @Usernamenotava1lable is on the right track!

It helps to notice that the answer to question 1 must be a squared number (from question 8)
Bugger - that was one of the first things I did notice when I read the problem.... but then miscopied q8, and meekly solved out to meet the condition that the answer to q8 was q2/q4.... ho hum.

Bloody hell you're a clever bunch.
I read halfway through and had to go for a lie down.

Definitely Boswell

@nillygin, put us out of our misery please.

Spoiler alert:

Answers:

Q1. 36
Q2. 2
Q3. T
Q4. 2
Q5. F
Q6. 6
Q7. F
Q8. -6
Q9. T
Q10. -4

But how do you come up with that answer? How do you know?

@nillygin

Spoiler alert:

Answers:

Q1. 36
Q2. 2
Q3. T
Q4. 2
Q5. F
Q6. 6
Q7. F
Q8. -6
Q9. T
Q10. -4

This doesn't work for Q9: Q4-Q2 = 0. Q8xQ4 = -12. 0 - (-12) = 12, which does not equal your answer to Q6. So Q9 would actually be false and would also make your answer to Q2 incorrect.

Here's my solution, which I think works:

Q1. 144
Q2. 2
Q3. T
Q4. 2
Q5. F
Q6. 24
Q7. F
Q8. -12
Q9. T
Q10. -16

Ah, bugger, I was doing it with my husband and when we checked the results that must have slipped through in translation! We started from knowing Q1 must be a squared number which was also a multiple of either 5 or 6 (from Q6). We were then effectively brute forcing it. If we’d calculated Q9 correctly I suspect we would have fairly quickly got to what you have @nikkim1990 well done!

Still no zeros though 😂

Thanks for the solution - I can now legitimately torture dh with it

My answer is totally different!

I think there are only 2 possible answers to question 1 and that PPs were right to say the answer to q 10 is whatever you need it to be.

If we start off with question 1 it says what is the sum of all the numerical answers including this one.

So the answer to question 1 has to be a number that does not influence the sum of the other numerical answers.

I started off trying 0.

The next key question is q 4. Again the answer to q 4 has to include its own answer and not influence the answer. The only way for this to work is if no other answer is the same, so the answer has to be 1 and no other question can be answered 1.

If you follow this logic through with zero, you get a plausible set of answers until you hit q 7 and q 8.

1. 0
2. 0
3. F
4. 1
5. F
6. 0
7. Oops, doesn’t work.
8. Could be 0 or false, if you accept that 0/0 is sometimes considered to be 0, or if you equate false with undefined.
9. False

10. -1

So then I thought about what other number could be the answer to 1 without influencing the answer to 1, and infinity/hyperreal numbers could work here.

1. ♾
2. 2
3. T
4. 1
5. T
6. ♾, but a smaller infinity than 1 ( my clever maths-y nephew told me about bigger and smaller infinities, mind blown) so q 3 can still be true
7. F
8. Smaller ♾
9. F

10. Smaller ♾, or I think any positive number you like.

Does this work? Let me know what you think!

Another way would be to say that 3 is false (because of the other ♾ answers) and 5 is true, then whack a negative number in as the answer to 10. That might even be better because it wouldn’t rely so much on different infinities.

Oh ignore the second option, that would throw out q 2 and q 4.

The next key question is q 4. Again the answer to q 4 has to include its own answer and not influence the answer. The only way for this to work is if no other answer is the same, so the answer has to be 1 and no other question can be answered 1.

I don't think that's right. 2 would work if another answer was 2. etc.

Hmm, that’s good logic. So, q 4 and q 2 could both have the answer 2, and the answer to q 7 could still be F.

Alternatively, using MindGrapes’ logic, you could say:

1. ♾
2. 2
3. T if you read the question as not meaning the single largest number
4. 2
5. T
6. ♾
7. F
8. ♾
9. F

10. Any positive integer

The flaw is my approach is that you need to accept that ♾ is an integer, as per the question, and that ♾/♾ is ♾. So, amy simpler solutions are welcome!

Is it not the solution posted by nikkim1990? It works, doesn't it?

1. 144
2. 2
3. T
4. 2
5. F
6. 24
7. F
8. -12
9. T

10. -16

Q10 is false - what is the answer to this question?

It’s a word puzzle the answer is false because the answer is not ‘what’

It's not a word puzzle. Q10 will be whatever the answer is needed to make the other answers right.
"What is the answer to this question?" isn't asking whether a statement is true or false. The other T/F questions are clearly worded as such.

@CoffeeRequiredNow

Is it not the solution posted by nikkim1990? It works, doesn't it?

1. 144
2. 2
3. T
4. 2
5. F
6. 24
7. F
8. -12
9. T

10. -16

Yes. This works. I must admit I checked on another forum to be sure. But then I went back and worked through the logic.

My logic:
Write out all possible answers for qs as soon as they were restricted. 3,5,7,9 are either true or false. 1,2,4,6,8 numerical and 10 unknown.
Q2 has to be 0,1,3,4 or 5 because there are only 5 answers that could be true.
Q4 has to be 1,2,3,4,5,6 because there are only 6 answers that could be numbers.
At this point, q10 must be a number and negative to balance out the positive numbers in 2 and 4 and the fact that the smallest that q1+q6+q8 could be is 0. This was a harder bit of logic than most of the rest of the puzzle.
This then means that q5 is false because at least one number is negative.
Because of q8, q1 must be square and q8 its square root. Q6 is the average, which is either q1/6 as there are 6 numbers. This rules out lots of square numbers. I listed the remaining ones at this point. 0,36,144... And then listed possible answers for Q6 (0,6,24...)and q8(0,6,12...). Obvs there are bigger possibilities.
Back to Q4. Can no longer be 6 as we know that q10 is negative. Then q1, Q6 and q8 can't be 1,2,3,4 or 5 so can't be same as Q4. So Q2 is the only one that could be same as Q4. So Q4 is 1 or 2.
Q2 can no longer be 4 or 5 as there are only 3 unresolved true/false qs left. If its 0,it breaks q7. If its 3, it breaks q7.
Another hard step here. Q4 and Q2 are 1 or 2 only. If Q4 is 1,then Q2 must be different and so can't be 1. If Q4 is 2,then Q2 must be 2. Which means that Q2 has to be 2 and q7 can't be true and therefore q3 and q9 must be true.
As q1 is now largest in quiz, it can't be 0 and neither can Q6 an q8.
The rest is all solved through the fact that q9 has to be true. Only works with solution above.

Good puzzle but very hard!

The intro has a caveat about question 10

@Trisolaris

The intro has a caveat about question 10

Oh yes, sorry.