Help with algebra problem please.

[Notplannedforthis]

Can anyone help with this maths problem?

I get the answer to be 11 as I do the 1x2 inside the brackets first to make the problem 8/2x2+3 = 4 x 2 + 3 = 8 + 3 = 11

However 11 is not an option.

I would say E

8/4 +3 = 5

E.
(1x2) = 2
2(2) = 4
8/4 = 2
2+3 = 5

(maths degree. I only say that as I know how these threads go)

The 8 is dived by all of 2(1x2)

The 2(2x1) should all be done together to give you 4. So you did bodmas but not quite correctly.

E

Thank you.

I'd have selected E, if I'd been doing the question as I'd have arrogantly assumed the question writer had forgotten the extra set of brackets when there was no 11 option 😮

DD got it wrong as couldn't think past there not being an 11 option. The problem I've faced has been explaining to DD, why she got it wrong.

Try writing the divided by bit as a fraction with a horizontal line instead.
The formatting will be shot but you would have
8
----- + 3
2(1x2)

that might make it clearer.

as in 8 over '2(1x2)' and then + 3 after the fraction.

E
8/4+3=5

Essentially she has done it as '2 x (2 x 1)' - which is different from '2(2 x 1)'. She needs to understand that where a number is stuck to a bracket, it becomes part of the bracket bit of the equation.