Maths help!

[AdventureTravelDreamer]

DS is stuck on a question for his maths homework and we would really appreciate someone to explain if possible. It is a rectangle that has sides
4x + 3y = 13
3x + 2y = 10

So he has worked out that x + y = 3 but that is as far as he has got.

We have also considered the 6x + 5y = 23 but still no closer to working out the values of x and y.

Please help oh wise MNers!! Plus any online tutorials to explain / practice would be fantastic.

TIA

Well according to the info given If x+y = 3 then

2x + 2y = 6

So the difference between the above and

3x + 2y= 10

Is x. So x would be 4

If x is 4 then y is -1

Not sure where the rectangle fits

This is simultaneous equations. I suggest corbettmaths - watch the online video on the topic for help and then try to answer it (a v good website that's free too)

Of course!! Thank-you!

Sorry I didn't explain the rectangle very well. The question was given as a diagram with one side showing 13 and the equal opposite side showing as 4x + 3y and the same with the shorter sides for 10 and 3x + 2y.

Thanks catcatcat I'll get him to have a look

He needs to multiply top equation by 2 and bottom equation by 3 and then subtract one equation from the other to remove the 'y' term.

Or topx3 and secondx4 and subtract to remove the 'x' term.

Then solve for the term you have left.
Plug the answer for that term back into one of the original equations and solve for the other.
Check by putting them both back into the other original equation.

You can substitute. If x + y = 3, then x = 3 - y.

Returning to the original equations, substitute the x with 3-y, and then see if you can take it from there.

There are many ways to solve simultaneous equations.