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Maths help please!

10 replies

JordanBaker · 19/11/2011 17:15

Could anyone explain how to solve the following please?

A year ago a mother was 4 times as old as her daughter. In 3 years time she will be 3 times as old as her daughter. How old is her daughter now?

We have the answer- it's the method we need.

TIA

OP posts:
Sparklingbrook · 19/11/2011 17:22

Sorry my brain has exploded. . A maths whizz will be along shortly, hopefully. Grin

empirestateofmind · 19/11/2011 17:27

If daughter is x years old now. Mum is y years old now.

A year ago daughter was x-1 years and mum was y-1 hence

4(x-1) = y-1
4x = y +3

3 years time: 3(x+3) = y+3
3x +6 =y

then solve these simultaneous eqns

substituting for y in the top one gives

4x = 3x +6 +3
x=9
daughter is 9

MorningPurples · 19/11/2011 17:32

Let x be the daughter's age.

Set out two sentences that are true for this year.

First statement tells us that a year ago, mother was 4 times daughter's age. The daughter would have been x-1 at that point, so mother would be 4(x-1). Now it's a year later, so mother is 4(x-1) + 1.

Second statement says that in three years, mother will be 3 times daughter's age. Daughter will be (x+3) then, so mother will be 3(x+3). That's still three years in the future, so now, mother is 3(x+3)-3.

Two different ways of finding mother's age this year, so you can set them equal to each other.

4(x-1) + 1 = 3(x+3) -3

Multiply out brackets.

4x - 4 + 1 = 3x + 9 -3

Simplify

4x -3 = 3x + 6

subtract 3x from both sides

x - 3 = 6

add 3 to both sides.

x = 9.

Daughter is now nine. A year ago, she was 8, and mother was therefore 32. So mother is now 33. In three years, daughter will be 12, and mother will be 36.

MorningPurples · 19/11/2011 17:32

cross posted, sorry, but same idea!

JordanBaker · 19/11/2011 17:55

Thank you both so much. Have a Wine from me. Now I can pretend I've cracked it cos it had DH stumped as well!

OP posts:
empirestateofmind · 19/11/2011 18:02

Thanks for the Wine JB!

Sparklingbrook · 19/11/2011 18:04

What year at secondary school is this question set for? (Wondering quite how thick I am).

JordanBaker · 19/11/2011 18:16

It's Y9. I was utterly stumped too if it's any consolation! Have successfully convinced DH that I worked it out. He is Shock

OP posts:
Sparklingbrook · 19/11/2011 18:18

Phew. DS1 is Year 8. I still have chance to enrol on a maths course in readiness. We were doing Igneous Rocks homework for Geography last week and I had trouble with that. Grin

JordanBaker · 19/11/2011 18:35

Don't worry about a maths course-just ask MN!

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