Help me with this maths problem please - my brain hurts!

[Celeriacacaca]

If a cat was sold for £60 but a loss of 20% was made on the sale, what was the original buying price?

I know it is 50 but am at a loss as to how to express it in written form so that DD will understand how to calculate it herself.

Can anyone help please? TIA.

Sorry have confused two problems - told you my brain was hurting.

Dog sold for £60, profit of 20% made on it, what was original buying price.

As before, know it is £50 but need it expressed in written formula form to explain to DD.

Other one was £72 - got that

If the cat was sold for £60 at a 20% loss, then the original price was higher!

20% is one fifth, so the £60 represents four-fifths. So, divide 60 by 4 to work out how much each of those fifths is (15). The original price was five-fifths = £75.

More formally 60 = (80/100) * P

So, P = (100/80) 60 = 5/4 60 = 75

The £60 is 80% of the selling price (£X) because it made 20% loss.

60 = 0.8 of X

60 / 0.8 = X

60 is 120/100 times the cost
so the cost is 60 / 120 X 100 = 50

60 is 120% of the buying price

(60 / 120) x 100 = original price.

Dog sold for £60, profit of 20% made on it, what was original buying price..

Price * (120/100) = 60

So Price = (100/120) 60 = (5/6) 60 = 50

In the prob, the 60 pounds represents 100% plus 20% so, 120%

So divide 60 by 120 to work out how much 1 % is (0.50) and multiply by 100 to get the original price.

Origional price / 1.A where A = the percentage.

So 60 / 1.2

If it made a 20% loss then multiply rather than /

Thank you so much and sorry for initial confusion!

Got it now and brain now feeling better.

Thank you.

Its always 1.something

Divide by that to reduce the number.
Multiply by that to increase the number.

120/100 (120%) x P (price) = £60

P = 60 x 100/120

= 6000/120

= £50