Hi theweekendisnear
I take your point - math is meant to be literal and understandable - but only in equation form. The issue here is the teacher/ workbook/ website has poorly expressed what they're saying (and maybe you're being a bit of a stickler for precision in directions).
So take the number 14
Double it - you get 28 (are you with me here?)
Then (IGNORE THE DOUBLE 14 instruction - but think and if I double that product (effectively 2 x 14 = 28 and then double the 28) what do I get)
Doubling 28 gives you 56
and if you double that product (2 x 56)
you get 112 (which exceeds the 100 limit arbitrarily set by teacher/ workbook/website/ etc...)
So how many doubles of 14 (and subsequent products - if that makes more sense) can be performed before exceeding 100
START with 14 (NO DOUBLES YET)
DOUBLE #1 (2 x 14) = 28
DOUBLE # 2 (2 x 28 - 28 being the product of the first doubling) = 56
DOUBLE #3 (2 x 56 - being the product of the second doubling) = 112
112 exceeds 100
therefore you can only double 14 (and subsequent products) 2 times
ANSWER = 2
Was that correct?
Is that clearer?
-------
It's really a principle of doubling, then doubling that product again, then doubling again until you exceed the limit.
An example of the technique would have helped (and maybe you can write a brief note to the teacher saying you found this a bit confusing and perhaps in future providing a worked example first might help).
HTH