Cake Tin conversion

[Sugarlover]

Mary Berry recipe for a marbled coffee ring cake - it says to use a cake tin size given below

1.75 litre (2 3/4 pint) ring mould cake tin

250g Margarine 250g caster sugar
4 eggs 250g self-raising flour

I can't find a 3 pint ring mould anywhere on the internet, and have absolutely no idea how to translate this into another kind of cake tin. Please can anyone help?

is a 3 pint ring mould cake tin equal to an 8 inch ring mould cake tin / savarin cake tin
OR
is a 3 pint ring mould cake tin equal to a 9 inch ring mould cake tin /savarin cake tin ?

My husband and me had this cake once and since then wanted to make it somehow but we could never get the cake tin . i will be grateful if anyone can help me

Thank you so much

Pints and litres are units of volume. To know the volume of an 8-inch circle you'd need to know the depth.

Eight inches is the diameter, so 4 inches is the radius. Four inches is 101.6 mm = 0.1016 m.

The volume of an 8-inch tin, in cubic metres is π× (0.1016)² ×d, where d is the depth in metres. Suppose we set the volume at 1.75 L and see what the depth would have to be. 1.75 L = 0.00175 m³.

So d = 0.00175 ÷ (3.14159 × (0.1016)²) = 0.05396 m = 5.396 cm.

For a 9-inch tin it's

So d = 0.00175 ÷ (3.14159 × (0.1143)² )= 0.05396 m = 4.264 cm.

If we look at 3-pint volumes instead of 1.75 L we start by converting pints to litres. One Imperial gallon is 4.54609 L, so a pint is 4.54609 ÷ 8 = 0.56826125 L and three pints is 1.70478375 L or 0.00170478375 m³.

For an 8-inch tin

So d = 0.00170478375 ÷ (3.14159 × (0.1016)²) = 0.05257 m = 5.257 cm.

For a 9-inch tin

So d = 0.00170478375 ÷ (3.14159 × (0.1143)²) = 0.04154 m = 4.154 cm.

The screenshot attached suggests a 7.5 inch bundt tin is 1.5 l.
So, I'd go with an 8 inch ring/bundt/savarin tin, and see how you go