Stuck on maths question

[hercules1]

Okay, got a question from the rules of maths book that I can't work out.

In a survey conducted in a junior school it was found that on one evening four times as many children watched BBC one as watched BBC2, and that twice as many children watched ITV as watch BBC one. If there were 310 children in the school, how many children watched each channel?

Any help gratefully received.

For a moment there I thought 'Oooooh a nice simultaneous equation'

Feel a teeny bit deflated now.

Anyone else yearn for a random opportunity to flex their long defunct O Level maths muscles.

Ah yes, that's it Edith, or maybe watching Dave!

It could be as few as 8 watched ITV, 4 watched BBC1 and 1 watched BBC2 - while the rest watched the other 8 million other channels (when was this book written with only 3 available channels??)

Sixth edition printed 1994. Dh bought in from Foyles in 2005 according to the price sticker.

I think you are all, save hercules1, missing the point. The OP never said that all the children in the school were watching TV. So if the number of BBC2 viewers is n then all we know is that the total number of viewers is 13*n and this must be less than or equal to 310. So n is ANY whole number from 0 to 23 and the number of BBC1 and ITV viewers follows from that choice of n. n=10 works just as well as 23. If the OP has missed a bit out from the actual question then only then is it a different story.

I meant iklboo and hercules1 - sorry iklboo. The problem is ill-posed - does not have a unique answer.