Any maths whizzes about please?

[SoManyCreepyBears]

DS and I are stuck on this question- we can calculate all the different angles but what is the question referring to when it says angle QPU?

We’re hoping the answer is 15!

The wobbly angle line was added by us- sorry to confuse.

I think 15, too.

Yes, 15 deg.

So the sharp angles on either end of the squished isosceles triangle on the left.

You know the internal angle of the square (90). You know the internal angles of the equilateral triangles (60). You know how many degrees make up a straight line (180) and a circle (360).

And then you can get the correct answer.

The angle you drew in is 150deg: 360-(60+90+60)
180-150=30/2=15

Yes, the answer is 15

By complete chance I saw this today in a junior maths challenge paper, don’t know if that’s where you got it from

the answers are here

https://www.ukmt.org.uk/sites/default/files/ukmt/JMC_2022_Solutions_0.pdf

And if I can type without posting before I've finished, that gives you the angle at the peak touching the square. With then means you subtract that from 180 to give the answer when you halve the remainder to get the other two angles of the triangle.

It’s 15

each circle or square has a total of 360
each triangle has 180 total

see attached

Angle QPU just means the angle created by points Q, P and U, which is the narrow one in the triangle by point P.

When they say angle QPU, you basically start at the first letter given, and move to the next one along. You will end up drawing an angle, and that's what you are calculating.
Yes, I agree with 15o.

Angle QPU means the angle created by QPU. I teach it as 'start at Q, travel to P and finish at U, so it's that angle there. The important letter is the one in the middle. Angle QUP would be different, for example.

Thank you! We only got sent the questions to practise and sometimes knowing the right answer and working back can really help.

That is the bit I couldn’t get- have explained this to DS now- thank you!