ssd,
www.leckieandleckie.co.uk
publish revision guides relevant to Scotland. I have found the following two for S1-S3:
www.leckieandleckie.co.uk/products/buy_online.asp?css=1&area=219&lvl=7&id=1985
www.leckieandleckie.co.uk/products/buy_online.asp?css=1&area=219&lvl=7&id=1986
The more readily available KS3 guides (England) would cover more or less the same topics. You can sometimes find them at The Works and Poundland at discounted prices.
However, I would suggest you follow your DS's own school text book.
As for the original question, I have looked at it again and think the last part might actually be a/4 (rather than a/3):
3a/4 = (3a - 6)/2 + a/4
The denominators are 4, 2 and 4. Their lowest common multiple (LCM) is 4. So to get rid of the denominators, multiply both sides by 4:
4 x 3a/4 = 4 x [(3a - 6)/2 + a/4]
3a = 2(3a - 6) + a
3a = 6a - 12 + a
3a = 7a - 12
Get all the 'a' terms on one side and the numbers on the other. Since there is a negative 12 on the right hand side, add 12 to both sides:
12 + 3a = 12 + 7a - 12
12 + 3a = 7a
Now subtract 3a from both sides to get the 'a' terms on one side:
12 = 4a
Dividing both sides by 4:
3 = a, written as:
a = 3
You can then check if the answer is correct:
(3 x 3)/4 = [(3x3) - 6]/2 + 3/4
9/4 = 3/2 + 3/4
9/4 = 6/4 + 3/4
9/4 = 9/4
As far as I know, a standard, age 13, algebra homework question similar to the one posted would NOT have 36/13 as an answer, either in England or in Scotland.
I haven't seen a similar question with a similar answer even in (age 15) Standard Grade Credit (Scotland) or GCSE (England)
exam papers.