OK, so you're looking for 2 numbers, both of which are factors of 144. I would approach this by looking at what are the prime factors of 144. So to do this I would first divide 144 by 2 to give 72, then divide by 2 again to give 36, again by 2 to give 18 and once more to give 9. Dividing 9 by 3 leaves 3, so 144=2^4*3^2 (where ^ = to the power of).
So from this I can see what numbers are going to the factors of 144. As 144 is the LCM I am looking for 2 numbers which do not have a smaller common multiple. I guess at this point experience kicks in, because I can see that 9 (3^2) and 16(4^2) are obviously factors. By checking all of the multiples of 16 up to 144 I can see that none are divisible by 9, so 9 and 16 are 2 numbers with 144 as their LCM.
Not the most elegant of solutions, but one which does at least practice HCFs.
Ladymuck that's genius! Thank you so much. I can now teach this to dd as I finally understand it. Very much appreciated as we were stuck despite googling. Are you a maths teacher or just good at maths?
They don't sell them here either, I'm just outside Edinburgh now! My Mum sends me aid parcels!! I don;t know if its true but I heard The Aberdeen Buttery Company does mail order! Can;t get decent Mealy pudding here either!