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Opinions (esp from maths teachers) on MathsGoGoGo

(7 Posts)
IslaValargeone Mon 20-Jun-11 17:13:24

I wondered how many people use these worksheets, and how you find them?

RoadArt Mon 20-Jun-11 20:41:54

Never heard of it, just had a look at site and it doesnt appeal. Too many links to get to what you want. Seems expensive for worksheets.
Not very appealing worksheets. One I opened was very confusing.

Tried a sample lesson but it froze and didnt show anything.

I would have to spend more time on it before making a true judgement but on first link to the site it isnt one that would motivate my children to use.

There are better sites available

RoadArt Mon 20-Jun-11 20:43:23

The video has finally loaded. It is too slow.

sarahfreck Tue 21-Jun-11 13:15:34

I use the worksheets in tutoring. They are well thought out and laid out and cover most of the national curriculum fairly well. I have found that supplementary material is needed for some children in some areas though.


You do not need to pay for a monthly subscription! If you visit Mathsphere here you can buy the same worksheets on a CD for £20

This would then last your dc the entire primary years!

sarahfreck Tue 21-Jun-11 13:18:04

PS - the CD doesn't have games, but there are lots of free online games for arithmatic basics such as tables that you could use instead.

IslaValargeone Tue 21-Jun-11 16:28:16

Thanks very much, especially Sarahfreck for saving me money! Wondered if I might pick your brains re a question, (ie) how do I do it?
Fred counts his models in groups of 5 and has one left over. He then counts them in groups of 3 and also has one left over. How many does he have?
It's from a year 5 worksheet, but I'm having a thick moment and don't get it blush

sarahfreck Tue 21-Jun-11 19:13:07

I'd guess at year 5, you should do it by trial and error ( though you could also do it algebraically).
So start counting up in 5's
5 then add 1 = 6
does this divide by 3 with 1 remainder - no
10 then add 1 = 11
does this divide by 3 with 1 remainder - no
and so on until you find one that works

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