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equation help needed, please!

(9 Posts)
CocktailQueen Thu 25-Feb-16 19:48:39

How would you solve: 4z/9 (over 9) - 5 = -2

DD is stumped.

I have done: 4z/9 = -2 + 5

4z/9 = 3

so it should be 27/9 = 3/1, but that doesn't work out for z. Gah.

Help??

MsMermaid Thu 25-Feb-16 19:51:23

From 4z/9 =3 you need to multiply by 9 to get
4z =27
Then divide by 4
So z =27/4 or 6 3/4

CocktailQueen Thu 25-Feb-16 19:53:56

Oh, so if you have a fraction like that, you can treat the bottom number like a normal number and move it to the other side of the equation? And you don't need to make it negative? Thank you...

RafaIsTheKingOfClay Thu 25-Feb-16 19:56:52

If you have 4z/9=3

Then mutiply both sides by 9 to leave you with 4z=27.

Then divide both sides by 4 to find z.

ilove Thu 25-Feb-16 19:56:54

27/4 so 6.75

4z/9=3 [multiply both sides by 9]
4z=27 [divide both sides by 4]
Z=27/4=6.75

Puppymouse Thu 25-Feb-16 20:13:44

I feel sick with worry for when my DD starts school reading this. I don't even understand the question and I have a degree sad

MsMermaid Thu 25-Feb-16 20:29:01

Don't worry. This is secondary school stuff, and if you can't help you send the child into school to ask the teacher for help. Ime most teachers will happily help if asked before the lesson it's due in. Nobody expects all parents to be able to help with all subjects.

Puppymouse Thu 25-Feb-16 20:36:20

That's reassuring Mermaid. Thank you

CocktailQueen Thu 25-Feb-16 20:53:25

It's Year 7 stuff!!!! Am a bit horrified tbh. But yes, when she's asked the teacher before they have been v helpful. Thanks all - much appreciated!

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